Tricky question? - cannon diagram, labeled
A cannon fires a bullet with a muzzle velocity 0.250g vi = 11m / s in the direction theta = 52degrees above the horizontal and the acceleration due to gravity is 9.8 m / s 2 ^ The trajectory of the shell curve downward due to gravity at t = 0.383, the tank is below the line by a vertical distance delta h. How do I calculate the distance delta h? In the diagram, there is a barrel and the height of the throat and not labeled (in the gorge), but a little away from him, and on the track and is held horizontally, so that it touches drawn up canyon. Since the barrel is not the straight line of 52 degrees and marked 11 m / s. Canyon there is a line distributed in the form of a parabola opening downward. In the middle of the height of the parabola and the height of the canyonY. Delta H then a little later, Delta and Delta between the direct line of 11m / s and is near the top. It is really confusing Can someone help me?
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